Bees each have different mutation chance, for a bee with 10% chance then 1 mutator with uranium will give you 100% chance (uranium is x10), a 5% bee will require 2, a 2% chance will require 5 (using uranium), or a 2% can use 1 nether star.
The mutation modifiers of the mutators multiply, they are
not added. Thus, two uranium increase the mutation chance by 10*10=100 (and not 10+10=20). Therefore, 2 mutators with uranium are enough to get 100% mutation rate for any bee. As do 10 soulframes (gives a multiplier of x57.66), 3 eyes of ender or 6 ender pearls (mutation multiplier x64) or a single nether star.
any math on how many chocolate frames required to kill bees in one bee tick(or whatever its called)? i`m currently using 8, but i`m not sure if its optimal
Have a look at
http://ftbwiki.org/Lifespan to see how many ticks your bees live. Each chocolate frame divides the number of ticks by two. Thus, if you have a bee with longer lifespan (60 ticks), you need 6 chocolate frames, which result in 60/(2*2*2*2*2*2) = 0.9375 ticks - killing the bee in the first tick. This means you need exactly:
Longest lifespan: 7 frames
Shortened to Longer lifespan: 6 frames
Shorter or Short lifespan: 5 frames
Shortest lifespan: 4 frames