Up to 9000

[lenscas]

1200

 

[erindalc]

1201

 

[lenscas]

1202

 

[erindalc]

1203

 

[lenscas]

1204

 

[erindalc]

1205

 

[duckfan77]

1206

 

[erindalc]

1207

 

[duckfan77]

1028

 

[Someone Else 37]

1209

 

[lenscas]

1210

 

[Someone Else 37]

1211

 

[lenscas]

1212

 

[Someone Else 37]

1213

 

[lenscas]

1+2+1=4

 

[Someone Else 37]

1215

 

[lenscas]

(((1+2)*1)! ) =6

I believe I did it right....

 

[Someone Else 37]

1217 Yeah, looks right to me.

 

[lenscas]

1218 hooray for that video that showed how to sums of 3 of the same character without adding any numbers all the way from 3 ones' to 3 nines.
To make it clear when dealing with lets say, 3 ones this is allowed
1^1^1
but
1^2^1^1
is not, as you put in a new number
the solution to the 1's is
(1+1+1)!

 

[Someone Else 37]

1219 Reminds me of a puzzle where you have to use exactly four 4s and no other numbers or digits to create as many different integers as possible.

0 = 44 - 44
1 = 44 / 44
2 = 4/4 + 4/4
3 = sqrt(4) + sqrt(4) - 4/4
4 = sqrt(4) + sqrt(4) + 4 - 4
5 = sqrt(4) + sqrt(4) + 4/4
etc.

I think I did that sort of thing in MMYLC at some point, although I dropped the restriction on using exactly four 4s.