The math does indeed work out to be two full uses from each single ingot of yellorium just as Skyqula posted. Any power of two makes a convenient basis:
cycle #1 = 64 yellorium ingots --> 64 cyanite ingots --> 32 blutonium ingots
cycle #2 = 32 blutonium ingots --> 32 cyanite ingots --> 16 blutonium ingots
cycle #3 = 16 blutonium ingots --> 16 cyanite ingots --> 8 blutonium ingots
cycle #4 = 8 blutonium ingots --> 8 cyanite ingots --> 4 blutonium ingots
cycle #5 = 4 blutonium ingots --> 4 cyanite ingots --> 2 blutonium ingots
cycle #6 = 2 blutonium ingots --> 2 cyanite ingots --> 1 blutonium ingot
cycle #7 = 1 blutonium ingot --> 1 cyanite ingot
So from our original 64 yellorium ingots and reprocessing we got an additional 63 blutonium. If our basis had been 128 then there would be an 8th cycle making the total 127 blutonium = (128+127)/128 = 1.992. An intial basis of 256 stops at (256+255)/256 = 1.996. The pattern is 2^n yellorium produces 2^n-1 blutonium during n+1 fuel cycles. Taking a massive basis of 2^16 (65,536) yellorium gives 65,535 blutonium = (65,536+65,535)/65,536 = 1.99998. So sure if you want to be picky about it you never get to two since this asympotically approaches two but I call it two uses per yellorium ingot.
BTW, if you are really worried about fuel efficiency keep your reactors 1 fuel rod high and use solid squares of them.
Initial Reactor = 100kRF/mB = 100,000,000 RF/yellorium ingot
Upgrade #1 = 110kRF/mB = 110,000,000 RF/yellorium ingot
Actively Cooled = 2000mB steam at a fuel burn rate of 0.04 mB/t; paired with the best enderium turbine = 662,500,000 RF/ yellorium ingot
1.325 billion RF from one yellorium ingot using reprocessing is pretty insane for sure. So each yellorium ore represents 2.65 billion RF and that is without considering the bonus cyanite dust for processing your yellorium ore in a SAG mill with dark steel grinding balls which is the most efficient way to process it.
cycle #1 = 64 yellorium ingots --> 64 cyanite ingots --> 32 blutonium ingots
cycle #2 = 32 blutonium ingots --> 32 cyanite ingots --> 16 blutonium ingots
cycle #3 = 16 blutonium ingots --> 16 cyanite ingots --> 8 blutonium ingots
cycle #4 = 8 blutonium ingots --> 8 cyanite ingots --> 4 blutonium ingots
cycle #5 = 4 blutonium ingots --> 4 cyanite ingots --> 2 blutonium ingots
cycle #6 = 2 blutonium ingots --> 2 cyanite ingots --> 1 blutonium ingot
cycle #7 = 1 blutonium ingot --> 1 cyanite ingot
So from our original 64 yellorium ingots and reprocessing we got an additional 63 blutonium. If our basis had been 128 then there would be an 8th cycle making the total 127 blutonium = (128+127)/128 = 1.992. An intial basis of 256 stops at (256+255)/256 = 1.996. The pattern is 2^n yellorium produces 2^n-1 blutonium during n+1 fuel cycles. Taking a massive basis of 2^16 (65,536) yellorium gives 65,535 blutonium = (65,536+65,535)/65,536 = 1.99998. So sure if you want to be picky about it you never get to two since this asympotically approaches two but I call it two uses per yellorium ingot.
BTW, if you are really worried about fuel efficiency keep your reactors 1 fuel rod high and use solid squares of them.
Initial Reactor = 100kRF/mB = 100,000,000 RF/yellorium ingot
Upgrade #1 = 110kRF/mB = 110,000,000 RF/yellorium ingot
Actively Cooled = 2000mB steam at a fuel burn rate of 0.04 mB/t; paired with the best enderium turbine = 662,500,000 RF/ yellorium ingot
1.325 billion RF from one yellorium ingot using reprocessing is pretty insane for sure. So each yellorium ore represents 2.65 billion RF and that is without considering the bonus cyanite dust for processing your yellorium ore in a SAG mill with dark steel grinding balls which is the most efficient way to process it.