I'm wondering what the logic is behind the GregTech overclocker system. In the Assembling Machine, a non-direct supply of LV can handle 4 overclockers just fine. However, in the Centrifuge, a direct connection to an MFE can't handle just 3 overclockers, and not even a direct MFSU supply can handle 4 of them. Is the math different for each machine?
GregTech Overclocker Math?
- Thread starter SpartanBlockhead
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Says right in the book: 2x the speed, 4x the power.
At three overclockers, your centrifuge is using 320 EU/t
BTW: I'm sure you're wrong about the assembling machine working with 4 overclockers off a LV. That's using 256EU/t for the smallest recipe (1EU/t base), and potentially as much as 2048EU/t for the largest recipe. And in fact, I just tested it and those are the number's it's actually using.
At three overclockers, your centrifuge is using 320 EU/t
BTW: I'm sure you're wrong about the assembling machine working with 4 overclockers off a LV. That's using 256EU/t for the smallest recipe (1EU/t base), and potentially as much as 2048EU/t for the largest recipe. And in fact, I just tested it and those are the number's it's actually using.
Each machine uses different amounts of EU per operation. And the overclocker increases speed but doubles the energy usage (I believe its double not sure) and so each machine has a different starting point so the overclockers do work differently for each machine.
Says right in the book: 2x the speed, 4x the power.
At three overclockers, your centrifuge is using 320 EU/t
Ah, I guess I overestimated how much power the Assembling Machine used; it is only 2 EU/t by default for all of the recipes I've used in it so far. Thanks
Update: Wait, so does each overclocker double or quadruple the energy use?
4x power usage.
If that's the case, then how is the Assembling Machine working? 2 EU/t x 4 = 8 EU/t x 4 = 32 EU/t x 4 = 128 EU/t
I only have it wired with slightly less than 32 EU/t.
If that's the case, then how is the Assembling Machine working? 2 EU/t x 4 = 8 EU/t x 4 = 32 EU/t x 4 = 128 EU/t
I only have it wired with slightly less than 32 EU/t.
It wouldn't. You are powering it with more than you think.
It wouldn't. You are powering it with more than you think.
Impossible, its power is being fed through an insulated copper cable.
Impossible, its power is being fed through an insulated copper cable.
I which case you've got less overclockers than you think.
I which case you've got less overclockers than you think.
Nope, all 4 are present and accounted for.
Make a eu reader and use it on the cable while the machine is running as that will tell you exactly what it is getting. In addition make gregs portable scanner and use it on the machine as it will tell you exactly how many overclockers it has.
Also note that the cable only determines the max packet size but does not control the max amount of energy that it can carry. So you can have a copper cable with over 8k eu flowing though it if you want with enough energy sources on it as long as each energy source does not exceed 32eu.
Also note that the cable only determines the max packet size but does not control the max amount of energy that it can carry. So you can have a copper cable with over 8k eu flowing though it if you want with enough energy sources on it as long as each energy source does not exceed 32eu.
Make a eu reader and use it on the cable while the machine is running as that will tell you exactly what it is getting. In addition make gregs portable scanner and use it on the machine as it will tell you exactly how many overclockers it has.
Also note that the cable only determines the max packet size but does not control the max amount of energy that it can carry. So you can have a copper cable with over 8k eu flowing though it if you want with enough energy sources on it as long as each energy source does not exceed 32eu.
I am for sure that there are 4 overclockers in it. Also, I tested it in creative with a BatBox powering it and it still worked for the 2 EU/t recipes. Try it out yourself if you don't believe me.
Then it is a bug as that should be drawing 512 eu/t (2 * 4 = 8 * 4 = 32 * 4 = 128 * 4 = 512).
I'm wondering what the eu\t and p is for that on the cable, please use a eu reader on it while the machine is running. I would do it but I am at work and unable to test it.
I'm wondering what the eu\t and p is for that on the cable, please use a eu reader on it while the machine is running. I would do it but I am at work and unable to test it.
The EU-reader confirms that only 32 EU/t is moving through the copper cable, coming from a BatBox, into an Assembling Machine with 4 overclockers with a 2 EU/t recipe. It almost seems as if the multiplier is only 2 instead of 4, since 2 * 2 = 4 * 2 = 8 * 2 = 16 * 2 = 32, which is exactly what the BatBox can output.
what the bird says. put in a more complex recipe and you should either see stuttering or the process will take much longer than it actually should given constant power.
only multiblock machines and the electrolyzer in gregtech require a steady power stream. all the others will use what it has and keep waiting.
only multiblock machines and the electrolyzer in gregtech require a steady power stream. all the others will use what it has and keep waiting.
only multiblock machines and the electrolyzer in gregtech require a steady power stream. all the others will use what it has and keep waiting.
Centrifuges as well
Centrifuges as well
I was just about to mention Centrifuges, they complain about "Insufficient Energy Line!" just like the Electrolyzer and multi-blocks.